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Sagot :
Initial Circuit Analysis
1. Series Circuit Components :
- One 6V battery
- Two identical buzzers
- Two identical lamps
2. Given Data :
- Voltage across one buzzer = 1V
3. Voltage in Series Circuits :
- In a series circuit, the total voltage provided by the battery is divided among the components based on their resistances.
- The total voltage of the battery is 6V.
Since the two buzzers are identical and the two lamps are identical, the voltage across the identical components will be the same.
Step-by-Step Solution:
Step 1: Voltage across both buzzers
- There are two identical buzzers, and the voltage across one buzzer is 1V.
- Therefore, the total voltage across both buzzers = 1V + 1V = 2V.
Step 2: Remaining voltage for lamps
- The total voltage of the battery is 6V.
- The voltage across both buzzers is 2V.
- Therefore, the remaining voltage for both lamps = 6V - 2V = 4V.
Step 3: Voltage across one lamp
- The two lamps are identical, so the voltage across one lamp will be half of the remaining voltage.
- Voltage across one lamp = 4V / 2 = 2V.
Adding Another 6V Battery in Series
When Arun adds another 6V battery in series with the first, the total voltage in the circuit doubles.
Step 4: New Total Voltage
- Initial total voltage = 6V
- Additional battery voltage = 6V
- New total voltage = 6V + 6V = 12V
Step 5: Voltage across one buzzer with new total voltage
- In the initial condition, the voltage across one buzzer was 1V when the total voltage was 6V.
- Since the voltage in the circuit is now doubled and the components are still the same (identical buzzers and lamps), the voltage across each component will also double.
- Therefore, the voltage across one buzzer = 1V * 2 = 2V.
Step 6: Effect on the current in the circuit
- Ohm's Law states V = IR, where V is voltage, I is current, and R is resistance.
- Since the circuit components are unchanged and the resistances remain the same, doubling the voltage will double the current.
- Therefore, the current in the circuit will increase.
Summary:
1.Voltage across one lamp initially : 2V
2. Voltage across one buzzer after adding the second battery : 2V
3. Effect on the current in the circuit : The current will double.
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