Bonsoir,
1)
[tex]\dfrac{1}{2}+\dfrac{1}{3} +\dfrac{1}{6}\\ \\ =\dfrac{1\times 3}{2\times 3}+\dfrac{1\times 2}{3\times 2}+\dfrac{1}{6}\\\\ = \dfrac{3}{6} +\dfrac{2}{6}+ \dfrac{1}{6}\\\\=\dfrac{6}{6}\\\\ =1 \in \mathbb{N}[/tex]
2)
[tex]\sqrt{16} -\sqrt{25}\\=4-5\\=-1\in\mathbb{Z}[/tex]
3) [tex]\dfrac{91}{7}=13\in \mathbb{N}[/tex]
4)
[tex]\dfrac{34}{2}-\sqrt{289}\\ \\ =17-17\\=0 \in \mathbb{N}[/tex]
En espérant t'avoir aidé.
