Bonjour,
[tex]x(\sqrt{3}+3-\sqrt{2}) = -2\sqrt{2}+3\sqrt{2}+\sqrt{3} \\\\x(\sqrt{3}+3-\sqrt{2}) = \sqrt{2}+\sqrt{3} \\\\\frac{x(\sqrt{3}+3-\sqrt{2})}{\sqrt{3}+3-\sqrt{2}} = \frac{\sqrt{2}+\sqrt{3}}{\sqrt{3}+3-\sqrt{2}} \\\\x = \frac{\sqrt{2}+\sqrt{3}}{\sqrt{3}+3-\sqrt{2}}\\\\x = \frac{(\sqrt{2}+\sqrt{3})*(\sqrt{3}-\sqrt{2}-3)}{-4-2\sqrt{6}}\\\\x = \frac{\sqrt{6} -2-3\sqrt{2}+3-\sqrt{6}-3\sqrt{3}}{-4-2\sqrt{6}} \\\\x= \frac{-2-3\sqrt{2}+3-3\sqrt{3}}{-4-2\sqrt{6}}[/tex]
[tex]x=\frac{1-3\sqrt{2}-3\sqrt{3}}{-4-2\sqrt{6}}\\\\x= \frac{(1-3\sqrt{2}-3\sqrt{3})*(-4+2\sqrt{6})}{-8}\\\\x=\frac{(1-3\sqrt{2}-3\sqrt{3})*2(-2+\sqrt{6})}{-8}\\\\x = \frac{(1-3\sqrt{2}-3\sqrt{3})*(-2+\sqrt{6})}{-4}\\\\x=\frac{-2+\sqrt{6}+6\sqrt{2}-3\sqrt{12}+6\sqrt{3}-3\sqrt{18}}{-4}\\\\x = \frac{-2+\sqrt{6}+6\sqrt{2}-6\sqrt{3}+6\sqrt{3}-3\sqrt{18}}{-4}\\\\x = \frac{-2+\sqrt{6}+6\sqrt{2}-3\sqrt{18}}{-4}\\\\x = \frac{-2+\sqrt{6}+6\sqrt{2}-9\sqrt{2}}{-4}[/tex]
[tex]x= \frac{-2+\sqrt{6}-3\sqrt{2}}{-4}\\\\x = - \frac{-2+\sqrt{6}-3\sqrt{2}}{4}[/tex]
J’espère t’avoir aidé.
Si tu as des questions n’hésites pas à me les demander.
Bonne journée et bonne continuation.
